A good answer might be:

First  value of message: Only One Object
Value of parameter: Only One Object
Second value of message: Only One Object

Only One Object

The program works as you expect. The diagram shows what is happening. The main() method creates a String object that contains the characters "Only One Object." A reference to this object is held in the reference variable messsage.

Remember that a reference to an object is a way to find the object in main memory. If a method has a reference to an object, then in can use that object.

When the print() method is invoked, the reference to the object is passed as the value of the parameter. This is just like call by value with a primitive data type, but now the value is a reference.

The invoked method print() uses its formal parameter st to find the object.


QUESTION 7:

If print() changes the value held in st, will this change the actual object?