A good answer might be:

description start at 1, count upward by 2's, quite when count exceeds 10
sequence 1 3 5 7 9
code for ( count= 1 ; count < 10; ; count+=2 )

Counting by Threes

Here is almost the same loop as in the previous example, but now the control variable is incremented by THREE.

int count;
for ( count = 0; count <= 12; count += 3 )  
{
  System.out.println( "count is: " + count ); 
}
System.out.println( "\nDone with the loop.\nCount is now" + count);

Here is a JavaScript version of this loop. Try to predict the output before you run the program. (Notice that the test is now <= ).




QUESTION 8:

Now show the for statement for each of the following sequences

start at 0, count upward by 1's, end at 7 for ( count = ___; count < ___; count++ )
start at 0, count upward by 2's, end at 14 for ( count = ___; count < ___; count += 2 )
start at 1, count upward by 2's, end at 15 for ( count = ___; count < ___; count += 2 )