A good answer might be:

Yes, because the method's parameter x now stands for a different array.


New Picture

 

 

Here is the picture again, but now it should show what happens just after the second method call: 

operate.print( ar2 );

The picture is not finished. It should show the parameter x referring to the second array.

All the other variables (in the main() method) are correct and do not need to be changed.



QUESTION 7:

Mentally draw in the correct reference from the parameter x to the array it now refers to.