The series,  
,
is an arithmetic series 
and the summation
 ![]()
is called the arithmetic series summation .
The summation can be solved as follows: First, we make the simple variable substitution i=n-j:
Note that the term in the first summation in Equation 
is independent of j.
Also, the second summation is identical to the left hand side.
Rearranging Equation 
, and simplifying gives
    
 
There is, of course, a simpler way to arrive this answer.
Consider the series,  
.
and suppose n is even.
The sum of the first and last element is n+1.
So too is the sum of the second and second-last element,
and the third and third-last element, etc.,
and there are n/2 such pairs.
Therefore,  
.
And if n is odd, then  
,
where n-1 is even.
So we can use the previous result for  
 to get
 
.